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<div style="direction: ltr;font-family: Tahoma;color: #000000;font-size: 10pt;">Hi again,<br>
<br>
I think I can answer myself to (some of) my questions. Could you check for the sake of completeness?<br>
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1) the counter of dofs is not 3 since it represents the whole set of degrees of freedom (on all the triangles), and not the local set, where the dimension of a P1 scalar space would be 3.<br>
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2) if the space to which the function belongs was declared as a Lagrange space, I can simply put 1 to all the dofs, so I get a constant sum (probably 1, I suppose), right?<br>
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3) now I have understood how to extract the dofs, but I still don't know if there is a direct method for performing the outer product. Has it already been defined?<br>
<br>
Many thanks for your help!<br>
<br>
Andrea<br>
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__________________________________________________________<br>
<br>
Andrea Sacconi<br>
PhD student, Applied Mathematics<br>
AMMP Section, Department of Mathematics, Imperial College London,<br>
London SW7 2AZ, UK<br>
a.sacconi11@imperial.ac.uk<br>
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