[Dune] Residual != 0
Christian Engwer
christian.engwer at uni-muenster.de
Wed Oct 19 11:09:18 CEST 2011
Hi Alex,
> Hi, I set the verbosity level to true & I see that it calculates till pow
> (10, -15). But, when i calculate the residual as A*x - b, I do not get
> residual as 0. Could some one please help?
ISTL is using a defect formulation for the iterative solvers. If your
system is badly conditioned the real defect and the updated defect can
differ significantly.
> RESULTS:
>
> E (w lagrange & self) E (w/o self) E_lagrange
> ||gradL|| ||gradLphi||
> phi[atom_node] *Residual_phi_i*
> === CGSolver
> 16 1.212512273e-15
please run again with verbosity=2
> === rate=0.1056936409, T=0, TIT=0, IT=16
what are the number below?
> 55.13802707 -24.07287785 -2.788880238e-13
> 17.45594764 0.08484197512 -7.936744468
> *9.99848961
> *
Cheers
Christian
>
> SOLVER:
>
> *template<class GV>
> void P1Elements<GV>::solve()
> {
> * // make linear operator from A*
> Dune::MatrixAdapter<Matrix,ScalarField,ScalarField> op(PoissonMatrix);
> *
> // initialize preconditioner*
> Dune::SeqILUn<Matrix,ScalarField,ScalarField> ilu1(PoissonMatrix, 1,
> 0.92);
> *
> // the inverse operator*
> Dune::BiCGSTABSolver<ScalarField> bcgs(op, ilu1, 1e-15, 5000, 0);
> Dune::InverseOperatorResult r;
>
> * // initialue u to some arbitrary value to avoid u being the exact
> // solution*
> u.resize(b.N(), false);
> u = 2.0;
>
> b *= -1.0;
> // finally solve the system
> bcgs.apply(u, b, r);
>
> // A.solve(u,b);*
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